24c^2+26c-15=0

Solution for 24c^2+26c-15=0 equation:

24c^2+26c-15=0

a = 24; b = 26; c = -15;
Δ = b2-4ac
Δ = 262-4·24·(-15)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-46}{2*24}=\frac{-72}{48}
=-1+1/2
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+46}{2*24}=\frac{20}{48}
=5/12
$